The curves are to keep continuous laminations through the entire length of a section from start to stop.Is the Shepherd's crook shape formed by the rear keel/mast/engine mount area an artistic touch or an engineering decision?
Appreciate your brainstorming Mark
Jim
Wasn't there an even smaller early version of this airplane?I own the only remaining Carbon Dragon (Jim Maupin) in australia. Despite the name there is very little carbon, mainly wood construction and very light.View attachment 1162712
Not that Im aware of. Not from Jim Maupin and Erve CulverWasn't there an even smaller early version of this airplane?
JR,The Briegleb BG-12 (and BG-12/16) is another wooden wonder of that era.
Did the Horten Ho4 ever fly there?JR,
Yes, you are correct. I had forgotten about the all wood Briegleb BG-12/16. At the beginning of WW2, Gus Briegleb also designed the all wood two place BG-8 glider for the USAAF Glider Training program. The USAAF tested the BG-8 glider. It performed too well to be a trainer so Briegleb Glider Company did not receive a contract. After the war Gus’ Sailplane Corporation of America designed and sold kits for the BG-6 and BG-7 gliders with the ubiquitous welded tube fuselage and wood wings.
After WW2 through the 1970s in Southern California, a vast majority of USAF, NASA, and local aerospace test pilots and engineers were heavily involved in soaring and flew out of El Mirage at the Briegleb Soaring Center. In fact in the early 1960s, Gus Briegleb was commissioned to build all the wood components for the NASA M2-F1 Lifting Body. The interior airframe of welded 4130 tubing was built by NASA, and Gus built the wood bulkheads and formed the mahogany skin.
A number of U.S. National Soaring Championships were held at the El Mirage Airport back in the 1960s - 70s.
I flew gliders out of El MIrage in the late 1970s - through the early 1980s.
Wayne
Mark,Did the Horten Ho4 ever fly there?
I know the Mississippi U campaigned it in the early 60's
View attachment 1162725
My favorite is the Ho6 though, coolest thing ever IMO......Wood and cloth, Ridiculous aspect ratio and glide ratio.
They found it would flutter at about 80, but you could dive through the flutter and it was stable to speeds over 110.
I don't think they tried to push it harder than that.....
View attachment 1162726
JR,
aluminum | spruce full | spruce hollow | |
b [mm] | 50.8 | 68.3 | 70 |
W [kg] | 2.2 | 1.8 | 1.4 |
aluminum | douglas fir full | douglas fir hollow | |
b [mm] | 50.8 | 64.6 | 70 |
W [kg] | 2.2 | 2.0 | 1.6 |
I would work in laminations because it equalized the wood as far as tension, twisting and other forces are concerned. It also stabilizes and somewhat weather proofs the wood. Cloth can be added for other tension, or torsion benefits.First I would like to thank everybody for their beautiful photos and stories, great stuff!
Next I would like to contribute some thoughts on wood vs. metal design.
Looking at the wooden gyro design I first thought that this would inevitably result in a heavier aircraft, so I started to calculate a simple example. The mast is mainly stressed in bending, thus I omitted the tensile stresses and calculated an equivalent wooden mast for a bensen type aircraft. To avoid unneccessary complicaton the calculation assumes a 2 inch square profile with 3/16th wall thickness made from T-6061, for which I looked up a bending (tensile) strength of 45.000 psi (310 N/mm^2). The weight of a 3' length of this profile, at a density for aluminum alloy of 2710 kg/m^3, is 2.2kg.
Sitka spruce has been the choice of premium wood for building aircraft for a long time so this is the material I wanted to compare to. The bending strength is given in
- ANC-18. 'The Mechanical Properties of 174 Australian Timbers' by E.Bolza and N.H. Kloot 1963
as 10.400 psi (74 N/mm^2), density is 27 lb/cuft (432 kg/m^3).
You can look up my calculation in the octave/Matlab(R) program below. The result surprised me! Even a full, non hollow, wood section is considerably lighter than the aluminum mast (see below). Lastly I calculated a wood section where the inner half was removed, i.e. had a rectangular hole of half of the section width. Here are the results:
Spruce
b al 50.8mm b w 68.3mm b w2 69.8mm
W al 2.2kg W w 1.8kg W w2 1.4kg
Douglas fir
b al 50.8mm b w 64.6mm b w2 66.0mm
W al 2.2kg W w 2.0kg W w2 1.6kg
for the 2 inch (50.8 mm) aluminum section you need 68 mm spruce and 70 mm for the hollow section, weight is 2.2kg for aluminum, 1.8 kg spruce and 1.4 kg hollow.
It is not possible to split up a beam in two parts of half the cross section, as in the drawing where the mast goes to the keel, because then your torsional regidity drops dramatically. It would also be very difficult to increase the cross section gradually, becaus you would have to glue end-grain which gives a much lower strength of the glue and there are, as far as I know, next to know rules for calculating the joint. If you want to go fully natural materials you could tie the connecting arc with some sort of rope. That might sound strange until you remember that the polynesian canoes, which crossed thousands of miles of the pacific ocean back and forth, where tied together by rope, not a single piece of metal was used. A somewhat more modern aproach would be to use the good old gusset plate for this connection.
So, some thoughts on wood design. Looking forward to your comments.
Jürgen
=== octave/Matlab(R) program ====
clc
gEarth=9.81;
f2m = 0.3048;
i2m = 0.0254;
i2mm = 25.4;
% distance down the mast where bending stress is evaluated
h = 3; % 3 feet mast length
b = 2; % 2 inch square tube
t = 3/16; % wall thickness
% all dimensions converted to mm
b=b*i2mm;
t=t*i2mm;
h=h*f2m*1000;
Is=1/12*(b^4 - (b-2*t)^4);
Ws= Is/(b/2);
As=b^2- (b-2*t)^2;
sigAl = 310; % N/mm^2
rhoAl = 2710; % kg/m^3
Wal = As*h*rhoAl/1.0e9; % konvert rho from kg/m^3 to kg/mm^3
% wood -> spruce
sigW = 72; % N/mm^2
rhoWlbc = 27; % lb/cuft
matStr = 'Spruce ';
% wood -> douglas fir
% sigW = 85;
% rhoWlbc= 32.5;
% matStr = 'Douglas fir';
rhoW = rhoWlbc*16; % 16 (kg/m^2)/(lb/cuft)
% the first moment of inertia of the wooden beam
% must be 310/74 times greater than that of
% the aluminum beam for the same strength
Wsw = sigAl/sigW*Ws;
% Wsw = b*h^2/6 = b^3/6
% b is the third root of w
bW = (6*Wsw)^(1/3);
Ww = bW*bW*h*rhoW/1.0e9;
% second moment of inertia of hollow beam is
% I2 = (b^4 - (1/2*b)^4)/12 = 15/16*b^4/12
% thus moment of inertia is I2/(b/2)= 15/16*b^3/6
bW2 = (16/15*6*Wsw)^(1/3);
Aw2 = 0.75*bW2*bW2;
Ww2 = Aw2*h*rhoW/1.0e9;
fprintf('%s\n',matStr)
fprintf('b al %5.1fmm b w %5.1fmm b w2 %5.1fmm\n',b,bW,bW2);
fprintf('W al %5.1fkg W w %5.1fkg W w2%5.1fkg\n',Wal,Ww,Ww2);
Young has introduced the idea of making the mast as flexible as possible to absorb rotor shake, so my favourite idea is to use a single piece of bamboo for the mast. You'd have:This would allow the fore and aft motion to absorb the 2.rev shake.
aluminum | bamboo full | bamboo hollow 2/3 | |
b [mm] | 50.8 | --- | 53 |
W [kg] | 2.2 | --- | 0.9 |
Bamboo is a great material for strength and weight, you could make lug intersections like a bike frame and build the whole frame from bamboo glued into the lug joints which could be welded AL, or composite.Young has introduced the idea of making the mast as flexible as possible to absorb rotor shake, so my favourite idea is to use a single piece of bamboo for the mast. You'd have:
- a naturally tapered cross section
- a naturally hollowed cross section
- a round cross section which is the optimum for a mast,
...in terms of bending and aerodynamics
- a single piece, no glue lines
the results for a quick and dirt bamboo calculation, bending strength 130 N/mm^2 density 630 kg/mm^3 assuming that the cross section is 2/3 of the full section are (preliminary)
Bamboo
aluminum bamboo full bamboo hollow 2/3 b [mm] 50.8 --- 53 W [kg] 2.2 --- 0.9
It is almost midnight and I will try a better calculation tomorrow.
PS: Tonight we went to a concert by Avi Avital, mandolin, and Ksenija Sidorova, accordeon, just awesome.